0=-5t^2+11t+8

Solution for 0=-5t^2+11t+8 equation:

0=-5t^2+11t+8

We move all terms to the left:

0-(-5t^2+11t+8)=0

We add all the numbers together, and all the variables

-(-5t^2+11t+8)=0

We get rid of parentheses

5t^2-11t-8=0

a = 5; b = -11; c = -8;
Δ = b2-4ac
Δ = -112-4·5·(-8)
Δ = 281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{281}}{2*5}=\frac{11-\sqrt{281}}{10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{281}}{2*5}=\frac{11+\sqrt{281}}{10}
$